A garden hose with an internal diameter of 1.9 cm is connected to a (stationary) lawn sprinkler that consists merely of a container with 20 holes, each 0.15 cm in diameter. If the water in the hose has a speed of 0.91 m/s, at what speed does it leave the sprinkler holes?

Explanation

To solve the problem, we will use the principle of conservation of mass, which states that the mass flow rate must be constant throughout the system. This means that the product of the cross-sectional area and the velocity of the fluid must be the same at both the hose and the sprinkler holes.

### Step-by-Step Solution:

1. **Calculate the Cross-Sectional Area of the Hose:**
The formula for the cross-sectional area \( A \) of a circle is given by:
\[
A = \frac{\pi d^2}{4}
...