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The oxidation number of an element in a ...

The oxidation number of an element in a compound decides its nature to acts as oxidant or reductant. Oxidation number is defined and the residual charge which an atom has or appears to have in a molecule whenal other atoms are removed from the molecule as ions. Oxidation number is frequently used interchangebly with oxidation state. The stock notations of oxidation number are based on the periodic property-electronegativity. An atom in a molecule can be assigned positive, negative or zero oxidation number by considering its environment. In few cases, oxidation number can evenn be fractional.
Oxidation number of oxygen in `K_(2)O, K_(2)O_(2),KO_(2),KO_(3)` are in the order:

A

`KO_(3)ltKO_(3)ltK_(2)O_(2)ltK_(2)O`

B

`KO_(2)ltKO_(3)ltK_(2)OltK_(2)O_(2)`

C

`K_(2)OltK_(2)O_(2)ltKO_(2)ltKO_(3)`

D

`KO_(3)ltK_(2)OltKO_(2)ltK_(2)O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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The oxidation number of an element in a compound decides its nature to acts as oxidant or reductant. Oxidation number is defined and the residual charge which an atom has or appears to have in a molecule whenal other atoms are removed from the molecule as ions. Oxidation number is frequently used interchangebly with oxidation state. The stock notations of oxidation number are based on the periodic property-electronegativity. An atom in a molecule can be assigned positive, negative or zero oxidation number by considering its environment. In few cases, oxidation number can evenn be fractional. Oxidation number of Y in YBa_(2)Cu_(2)O_(7) is +3, then oxidation number of Cu is:

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