Home
Class 12
CHEMISTRY
A sample of H(2)O(2) is x % by mass. If ...

A sample of `H_(2)O_(2)` is x % by mass. If x ml of `KMnO_(4)` are required to oxidize 1 gm of this `H_(2)O_(2)` sample, calculate the normality of `KMnO_(4)` solution.

A

0.46 N

B

0.5 N

C

0.6 N

D

0.65 N

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE LEVEL -II (LECTURE SHEET (ADVANCED) MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS)|5 Videos
  • STOICHIOMETRY

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE LEVEL -II (LECTURE SHEET (ADVANCED) LINKED COMPREHENSION TYPE QUESTIONS)|5 Videos
  • STOICHIOMETRY

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL-I (MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS)|15 Videos
  • STATES OF MATTER

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE -PRACTICE SHEET (ADVANCED) (LINKED COMPREHENSION TYPE QUESTIONS) (PASSAGE- IV)|2 Videos
  • SURFACE CHEMISTRY

    AAKASH SERIES|Exercise Objective Excersice - 4 (ASSERTION (A)& REASON (R ) TYPE QUESTION)|34 Videos

Similar Questions

Explore conceptually related problems

Number of moles of KMnO_(4) required to oxidize one mole of Fe(C_(2)O_(4)) in acidic medium is

10 g sample of H_(2)O_(2) just decolorised 100 ml of 0.1 M KMnO_(4) in acidic medium % by mass of H_(2)O_(2) in the sample is

How many moles of KMnO_(4) are required to liberate one gram mole of oxygen from H_(2)O_(2) in acid medium ?

To 50 ml. of 0.1 N Na_(2)CO_(3) solution 150 ml. of H_(2)O is added. Then calculate the normality of resultant solution.

.4 sample of H_(2)O_(2) solution containing H_(2)O_(2) by weight requires x ml of KMnO_(4) solution for completed oxidation under acidic condition. The formality of KMnO_(4) solution is

100 mL of H_(2)O_(2) is oxidized by 100 mL of 1M KMnO_(4) in acidic medium ( MnO_(4)^(-) reduced to Mn^(+2) ) 100 mL of same H_(2)O_(2) is oxidized by v mL of 1M KMnO_(4) in basic medium ( MnO_(4)^(-) reduced to MnO_(2) ). Find the value of v: