If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?

Explanation

Given : 1 = 0.5 A, t = 2 h = 2 x 60 x 60 s = 7200 s
Quantity of electricity = I x t = (0.5 A) x (7200 s) = 3600 C A flow of 1 F, i.e., 96500 C is equivalent of flow of 1 mole of electrons, `6.02 xx 10^(23)` electrons
`therefore 3600 C` is equivalent to flow of `=(6.02 xx 10^(23))/96500 xx 3600` electrons `=2.246 xx 10^(22)` electrons.