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Consider the reaction :Cr(2)O(7)^(2-) + ...

Consider the reaction :`Cr_(2)O_(7)^(2-) + 14H^(+) + 6e^(-) to 2Cr^(3+) + 7H_(2)O`
What is the quantity of electricity in coulombs needed to reduce 1 mol of `Cr_(2)O_(7)^(2-)` ?

Text Solution

Verified by Experts

One `Cr_(2)O_(7)^(2-)` ion requires 6 electrons for reduction as shown by the above chemical equation. Thus, 1 mol of `Cr_(2)O_(7)^(2-)` ions require 6 F= 6 x 96500 C = 579000 C of electricity for reduction to `Cr^(3+)`.
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