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Electrolysis of KBr (aq) gives Br(2) at ...

Electrolysis of KBr (aq) gives `Br_(2)` at anode but of KF (aq) does not give `F_(2)` . Give reason for disparity in behaviour.

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`L_(F_(2)//F^(-))^(@)` has the highest reduction potential. Therefore, `F_(2)` is not liberated. Reduction potential of `O_(2)` is higher than that of `Br_(2)` . Thus, electrolysis of KBr (aq) gives `Br_(2)` and not `O_(2)`
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U-LIKE SERIES-ELECTROCHEMISTRY -CASE BASED/SOURCE-BASED INTEGRATED QUESTIONS (VERY SHORT ANSWER QUESTIONS (1 MARK EACH))
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