The conductivity of a 0.01 M solution of acetic acid at 298 K is `1.65 xx 10^(-4 )S cm^(-1)`. Calculate molar conductivity `(Lambda_(m))` of the solution.

Explanation

Use the relation,
`Lambda_(m) = (1000 k)/C`, where C stands for concentration
Substituting the values, we get
`Lambda_(m) = (1000 xx 1.65 xx 10^(-4))/0.01 = 16.5 S cm^(2) mol^(-1)`