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Calculate the degree of dissociation (al...

Calculate the degree of dissociation (`alpha`) of acetic acid if its molar conductivity (`Lambda_(m)` ) is 39.05 S `cm^(2) mol^(-1)`.
Given: `lambda^(@)(H^(+)) = 349.6 S cm^(2) mol^(-1)` and `lambda^(@)(CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)`

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`Lambda_(m)^(@) = lambda_(CH_(3)COOH)^(@) = 349.6 + 40.9 = 390.5 S cm^(2) mol^(-1)`
Degree of dissociation `(alpha) = (Lambda_(m))/(Lambda_(m)^(@)) = (39.05)/(390.5) = 0.1`
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Calculate the degree of dissociation (alpha) of acetic acid if its molar conductivity (^^_(m)) is 39.05 S cm^(2) mol^(-1) Given lamda^(@) (H^(+)) = 349.6 cm^(2) mol^(-1) and lamda^(2) (CH_(3)COO^(-)) = 40.9 S cm^(2) mol^(-1)

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Calculate degree of dissociation of 0.02 M acetic acid at 298 K given that mho_(m)(CH_(3)COOH)=17.37 cm^(2) mol^(-1),lambda_(m)^(@)(H+)=345.8 S cm^(2) mol^(-1), lambda_(m)^(@)(CH_(3)COO^(-))=40.2 Scm^(2) mol^(-1)

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