On the basis of the standard electrode potential values stated for acid solution, predict whether `Ti^(4+)` species may be used to oxidise `Fe^(II)` to `Fe^(III)` .
Reaction `{:(E^(@)//V),(Ti^(3+) + e^(-) to Ti^(3+), +0.01),(Fe^(3+) + e^(-) to Fe^(2+), +0.77):}`

Explanation

We shall find out the emf of the cell obtained by the combination of the two.
`E_("cell")^(@) = E_("Fe^(3+)//Fe^(2+))^(@) - E_(Ti^(4++)//Ti^(3++))^(@) = +0.77 V - 0.01 V = +0.76 V`
As the emf of cell is positive therefore, `Ti^(4+)` can be used to oxidise `Fe^(2+)` to `Fe^(3+)` ion.
`Ti^(4+) + Fe^(2+) to Ti^(3+) + Fe^(3+)`.