(i) The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 `Omega`. What is the cell constant, if the conductivity of 0.001 M KCl solution at 298 K is `0.146 xx 10^(-3) S cm^(-1)` ?
(ii) Predict the products of electrolysis in the following
A solution of `H_2SO_(4)` with platinum electrodes.

Explanation

(i) Cell constant = Conductivity (or specific conductivity) x Resistance
`=0.146 xx 10^(-3) S cm^(-1) xx 1500 Omega = 0.219 cm^(-1)`
(ii) At cathode: `2H^(+) (aq) + 2e^(-) to H_(2)(g)`
At anode: `2OH^(-)(aq) to O_(2)(g) + 2H^(+) (aq) + 4e^(-)`
Thus, `H_(2)` is evolved at the cathode and `O_(2)` at the anode.