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State Henry's law. Calculate the solubil...

State Henry's law. Calculate the solubility of `CO_2` in water at 298 K under 760 mm Hg. `[K_(H)` for `CO_2` in water at 298K is `1.25 xx 10^(6)` mm Hg]

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Henry.s law : At constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above· the surface of the liquid or solution.
`p=K_(H).x`
here, `p=760 mm, K_(H)=1.25 xx 10^(6)` mm
Substih1ting the values in the equation above, we have
`x=(p)/( K_(H) )= (760mm)/(1.25 xx 10^(6) mm) = 608 xx 10^(-6) =6.08 xx 10^(-4)`
Mole fraction of `CO_2` in water `=(n)/(n+55.5) = (n)/(55.5)` (n can be neglected as compared to 55.5) n is the number of moles of `CO_2` and 55.5 is the number of moles of water in one litre. `6.08 xx 10^(-4) = (n)/(55.5)` or `n=337.44 xx 10^(-4) mol` or `3.37 xx 10^(-2)` mol `L^(-1)`
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