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Let A = {a,b,c} and B = {4, 5}. Consider...

Let A = {a,b,c} and B = {4, 5}. Consider a relation R defined from set A to set B, then R can be equal to set

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A

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B

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`AxxB`

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`BxxA`

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The correct Answer is:
To solve the problem, we need to analyze the sets and the relation defined from set A to set B. ### Step-by-Step Solution: 1. **Identify the Sets:** - Let \( A = \{ a, b, c \} \) - Let \( B = \{ 4, 5 \} \) 2. **Define the Relation \( R \):** - A relation \( R \) from set \( A \) to set \( B \) consists of ordered pairs \( (x, y) \) where \( x \) belongs to \( A \) and \( y \) belongs to \( B \). 3. **Determine Possible Ordered Pairs:** - The possible ordered pairs can be formed by pairing each element of \( A \) with each element of \( B \): - From \( a \): \( (a, 4) \), \( (a, 5) \) - From \( b \): \( (b, 4) \), \( (b, 5) \) - From \( c \): \( (c, 4) \), \( (c, 5) \) - Therefore, the complete set of ordered pairs that can form the relation \( R \) is: \[ R = \{ (a, 4), (a, 5), (b, 4), (b, 5), (c, 4), (c, 5) \} \] 4. **Check the Cartesian Product \( A \times B \):** - The Cartesian product \( A \times B \) is defined as: \[ A \times B = \{ (x, y) | x \in A, y \in B \} \] - Thus, \( A \times B \) is exactly the set of ordered pairs we listed above: \[ A \times B = \{ (a, 4), (a, 5), (b, 4), (b, 5), (c, 4), (c, 5) \} \] 5. **Check the Cartesian Product \( B \times A \):** - The Cartesian product \( B \times A \) is defined as: \[ B \times A = \{ (x, y) | x \in B, y \in A \} \] - This would yield: \[ B \times A = \{ (4, a), (4, b), (4, c), (5, a), (5, b), (5, c) \} \] - None of these pairs are in the relation \( R \) defined from \( A \) to \( B \). 6. **Conclusion:** - Therefore, the relation \( R \) can be equal to the Cartesian product \( A \times B \) but not to \( B \times A \). - The final answer is that \( R \) can be equal to \( A \times B \).
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