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A & B are subsets of universal set U suc...

A & B are subsets of universal set U such that n(U) = 800, n(A) = 300, n(B) = 400 & n(A `cap` B) = 100. The number of elements in the set `A^(c ) cap B^(c )` is

A

100

B

200

C

300

D

400

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of elements in the set \( A^c \cap B^c \), we can use the relationship between the universal set, the sets \( A \) and \( B \), and their complements. Here’s the step-by-step solution: ### Step 1: Understand the Given Information We are given: - \( n(U) = 800 \) (the number of elements in the universal set \( U \)) - \( n(A) = 300 \) (the number of elements in set \( A \)) - \( n(B) = 400 \) (the number of elements in set \( B \)) - \( n(A \cap B) = 100 \) (the number of elements in the intersection of sets \( A \) and \( B \)) ### Step 2: Calculate \( n(A \cup B) \) Using the formula for the union of two sets: \[ n(A \cup B) = n(A) + n(B) - n(A \cap B) \] Substituting the values: \[ n(A \cup B) = 300 + 400 - 100 \] \[ n(A \cup B) = 700 \] ### Step 3: Calculate \( n(A^c \cap B^c) \) The complement of the union of two sets is given by: \[ A^c \cap B^c = U - (A \cup B) \] Thus, we can express the number of elements in \( A^c \cap B^c \) as: \[ n(A^c \cap B^c) = n(U) - n(A \cup B) \] Substituting the values we have: \[ n(A^c \cap B^c) = 800 - 700 \] \[ n(A^c \cap B^c) = 100 \] ### Final Answer The number of elements in the set \( A^c \cap B^c \) is \( 100 \). ---
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