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If A={1,2},B ={1,3} then (A xxB) cup (Bx...

If A={1,2},B ={1,3} then `(A xxB) cup (BxxA)` is equal to

A

{(1, 3), (2, 3), (3, 1), (3, 2), (1, 1), (2, 1), (1, 2)

B

{(1,3), (3,1), (3, 2), (2, 3)}

C

{(1,3), (2, 3), (3,1), (3, 2), (1,1)}

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the union of the Cartesian products \( A \times B \) and \( B \times A \). Let's go through the steps systematically. ### Step 1: Define the Sets We have two sets: - \( A = \{1, 2\} \) - \( B = \{1, 3\} \) ### Step 2: Find \( A \times B \) The Cartesian product \( A \times B \) consists of all ordered pairs \( (x, y) \) where \( x \) is from set \( A \) and \( y \) is from set \( B \). Calculating \( A \times B \): - Pairing \( 1 \) from \( A \) with each element in \( B \): - \( (1, 1) \) - \( (1, 3) \) - Pairing \( 2 \) from \( A \) with each element in \( B \): - \( (2, 1) \) - \( (2, 3) \) Thus, \[ A \times B = \{(1, 1), (1, 3), (2, 1), (2, 3)\} \] ### Step 3: Find \( B \times A \) The Cartesian product \( B \times A \) consists of all ordered pairs \( (x, y) \) where \( x \) is from set \( B \) and \( y \) is from set \( A \). Calculating \( B \times A \): - Pairing \( 1 \) from \( B \) with each element in \( A \): - \( (1, 1) \) - \( (1, 2) \) - Pairing \( 3 \) from \( B \) with each element in \( A \): - \( (3, 1) \) - \( (3, 2) \) Thus, \[ B \times A = \{(1, 1), (1, 2), (3, 1), (3, 2)\} \] ### Step 4: Find the Union \( (A \times B) \cup (B \times A) \) Now we need to find the union of the two sets obtained in the previous steps. Combining the elements: \[ (A \times B) \cup (B \times A) = \{(1, 1), (1, 3), (2, 1), (2, 3)\} \cup \{(1, 1), (1, 2), (3, 1), (3, 2)\} \] Listing all unique elements: - \( (1, 1) \) (already counted) - \( (1, 3) \) - \( (2, 1) \) - \( (2, 3) \) - \( (1, 2) \) - \( (3, 1) \) - \( (3, 2) \) Thus, \[ (A \times B) \cup (B \times A) = \{(1, 1), (1, 3), (2, 1), (2, 3), (1, 2), (3, 1), (3, 2)\} \] ### Final Answer The final result is: \[ (A \times B) \cup (B \times A) = \{(1, 1), (1, 3), (2, 1), (2, 3), (1, 2), (3, 1), (3, 2)\} \]
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