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Two cards are drawn from a pack of 52 ca...

Two cards are drawn from a pack of 52 cards. The probability that one card is an ace and other is queen is

A

`(""^(4)C_(2))/(""^(52)C_(2))`

B

`(2)/(""^(52)C_(2))`

C

`(1)/(663)`

D

`(8)/(663)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that one card drawn is an Ace and the other is a Queen from a standard deck of 52 cards, we can follow these steps: ### Step 1: Determine the Total Number of Ways to Draw Two Cards The total number of ways to draw 2 cards from a pack of 52 cards can be calculated using the combination formula: \[ \text{Total ways} = \binom{52}{2} = \frac{52 \times 51}{2} = 1326 \] ### Step 2: Determine the Number of Favorable Outcomes To find the number of favorable outcomes where one card is an Ace and the other is a Queen, we can choose: - 1 Ace from the 4 available Aces: \(\binom{4}{1} = 4\) - 1 Queen from the 4 available Queens: \(\binom{4}{1} = 4\) Thus, the total number of favorable outcomes is: \[ \text{Favorable outcomes} = \binom{4}{1} \times \binom{4}{1} = 4 \times 4 = 16 \] ### Step 3: Calculate the Probability The probability of drawing one Ace and one Queen can be calculated using the formula: \[ \text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{16}{1326} \] ### Step 4: Simplify the Probability Now, we simplify the fraction: \[ \frac{16}{1326} = \frac{8}{663} \] ### Final Answer Thus, the probability that one card is an Ace and the other is a Queen is: \[ \frac{8}{663} \] ---
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