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A letter is taken out at random from 'AS...

A letter is taken out at random from 'ASSISTANT' and and another letter taken out from the letters of the word 'STATISTICS'. The probability that they are identical letters , is

A

`13/90`

B

`1/45`

C

`19/90`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that a letter taken from the word "ASSISTANT" and a letter taken from the word "STATISTICS" are identical, we can follow these steps: ### Step 1: Identify the letters in each word - The letters in "ASSISTANT" are: A, S, S, I, S, T, A, N, T - The letters in "STATISTICS" are: S, T, A, T, I, S, T, I, C, S ### Step 2: Count the occurrences of each letter in both words - In "ASSISTANT": - A: 2 - S: 3 - I: 1 - T: 2 - N: 1 - In "STATISTICS": - S: 3 - T: 3 - A: 1 - I: 2 - C: 1 ### Step 3: Identify common letters The common letters between "ASSISTANT" and "STATISTICS" are A, S, I, and T. ### Step 4: Calculate the probability for each common letter 1. **For letter A:** - Probability of picking A from "ASSISTANT": \( P(A) = \frac{2}{9} \) - Probability of picking A from "STATISTICS": \( P(A) = \frac{1}{10} \) - Combined probability: \( P(A \text{ from both}) = \frac{2}{9} \times \frac{1}{10} = \frac{2}{90} \) 2. **For letter S:** - Probability of picking S from "ASSISTANT": \( P(S) = \frac{3}{9} = \frac{1}{3} \) - Probability of picking S from "STATISTICS": \( P(S) = \frac{3}{10} \) - Combined probability: \( P(S \text{ from both}) = \frac{1}{3} \times \frac{3}{10} = \frac{3}{30} = \frac{1}{10} \) 3. **For letter I:** - Probability of picking I from "ASSISTANT": \( P(I) = \frac{1}{9} \) - Probability of picking I from "STATISTICS": \( P(I) = \frac{2}{10} = \frac{1}{5} \) - Combined probability: \( P(I \text{ from both}) = \frac{1}{9} \times \frac{1}{5} = \frac{1}{45} \) 4. **For letter T:** - Probability of picking T from "ASSISTANT": \( P(T) = \frac{2}{9} \) - Probability of picking T from "STATISTICS": \( P(T) = \frac{3}{10} \) - Combined probability: \( P(T \text{ from both}) = \frac{2}{9} \times \frac{3}{10} = \frac{6}{90} = \frac{1}{15} \) ### Step 5: Sum the probabilities of picking identical letters Now we add the probabilities of picking each common letter: \[ P(\text{identical letters}) = P(A) + P(S) + P(I) + P(T) \] \[ = \frac{2}{90} + \frac{9}{90} + \frac{2}{90} + \frac{6}{90} \] \[ = \frac{2 + 9 + 2 + 6}{90} = \frac{19}{90} \] ### Final Answer The probability that the letters picked from "ASSISTANT" and "STATISTICS" are identical is \( \frac{19}{90} \). ---
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