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Cards are drawn one-by-one without repla...

Cards are drawn one-by-one without replacement from a well shuffled pack of 52 cards. Then the probability that a face card ( Jack, Queen or King) will appear for the first time on the third turn is equal to

A

`(300)/(2197)`

B

`(36)/(85)`

C

`(12)/(85)`

D

`(4)/(51)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the probability that a face card (Jack, Queen, or King) will appear for the first time on the third turn when drawing cards one-by-one without replacement from a well-shuffled pack of 52 cards, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Cards and Face Cards:** - A standard deck has 52 cards. - There are 12 face cards (3 face cards: Jack, Queen, King from each of the 4 suits). - Therefore, the number of non-face cards is \( 52 - 12 = 40 \). 2. **Determine the Required Outcome:** - We want the first two cards drawn to be non-face cards, and the third card drawn to be a face card. 3. **Calculate the Probability of Drawing Non-Face Cards First:** - For the first card, the probability of drawing a non-face card is: \[ P(\text{1st card is non-face}) = \frac{40}{52} \] - After drawing one non-face card, there are 51 cards left (39 non-face cards remaining). Thus, the probability for the second card is: \[ P(\text{2nd card is non-face}) = \frac{39}{51} \] 4. **Calculate the Probability of Drawing a Face Card on the Third Turn:** - After drawing two non-face cards, there are still 12 face cards left in the remaining 50 cards. Thus, the probability for the third card being a face card is: \[ P(\text{3rd card is face}) = \frac{12}{50} \] 5. **Combine the Probabilities:** - The total probability that the first two cards are non-face cards and the third card is a face card is the product of the individual probabilities: \[ P(\text{first face card on 3rd turn}) = P(\text{1st non-face}) \times P(\text{2nd non-face}) \times P(\text{3rd face}) \] - Substituting the values: \[ P = \frac{40}{52} \times \frac{39}{51} \times \frac{12}{50} \] 6. **Simplify the Expression:** - First, simplify each fraction: \[ P = \frac{40 \times 39 \times 12}{52 \times 51 \times 50} \] - Now calculate: - \( 40 \) and \( 52 \) can be simplified to \( \frac{10}{13} \). - \( 12 \) and \( 50 \) can be simplified to \( \frac{6}{25} \). - Therefore, the expression becomes: \[ P = \frac{10 \times 39 \times 6}{13 \times 51 \times 25} \] 7. **Calculate the Final Probability:** - Now calculate the numerator and denominator: - Numerator: \( 10 \times 39 \times 6 = 2340 \) - Denominator: \( 13 \times 51 \times 25 = 16575 \) - Thus, the probability is: \[ P = \frac{2340}{16575} \] - Simplifying this fraction gives: \[ P = \frac{12}{85} \] ### Final Answer: The probability that a face card will appear for the first time on the third turn is \( \frac{12}{85} \).
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MTG-WBJEE-STATISTICS AND PROBABILITY-WB JEE Previous Years Questions ( CATEGORY 1 : Single Option Correct Type ( 1 Mark) )
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