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A substance on analysis, gave the follow...

A substance on analysis, gave the following percentage composition, Na = 43.4%, C = 11.3%, O = 43.3% calculate its empirical formula [Na = 23, C = 12, O = 16].

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`Na_2CO_3`
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A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16].

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NCERT GUJARATI-CHEMICAL CALCULATION -Problems of Practice
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  2. Calculate the following Number of atoms in 7.46 g Li

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  3. A substance on analysis, gave the following percentage composition, Na...

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  4. What is the simplest formula of the compound which has the following p...

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  5. A compound on analysis gave the following percentage composition: C - ...

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  6. An organic compound was found to have contained carbon = 40.65%, hydro...

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  7. A compound contains 32% carbon, 4% hydrogen and rest oxygen. Its vapou...

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  8. An acid of molecular mass 104 contains 34.6% carbon, 3.85% hydrogen an...

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  9. What is the simplest formula of the compound which has the following p...

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  10. Calculate the oxidation number of underlined elements in the following...

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  11. Calculate the oxidation number of underlined elements in the following...

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  12. Calculate the oxidation number of underlined elements in the following...

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  13. Calculate the oxidation number of underlined elements in the following...

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  14. Calculate the oxidation number of underlined elements in the following...

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  15. Balance the equations Mg + NO3^(-) to Mg^(2+) + N2O + H2O) ( in acidi...

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  16. Balance the equations Cr^(3+) + Na2O2 to CrO4^(-) + Na^(+)

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  17. Balance the equation S^(2-) + NO3^(-) to NO + S8

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  18. Balance the equations FeS + O2 to Fe2O3 + SO2 ( molecular form )

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  19. Balance the equations Cl2 + OH^(-) to Cl^(-) + ClO3^(-) + H2O

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  20. Calculate the volume of 14.3 M NH3, solution needed to prepare 1L of 0...

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