Calculate the number of neutrons in the remaining atom after emission of an `alpha` particle from `92^(X^(238))`` atom. also report the mass number and atomic number of the product atom.

Explanation

`92^(X^(238)) rarrA^(X^(m))+2^(He^(4))`
comparing mass number of both sides
238 =m+4
m=238-4 =234
comparing atomic number on both sides
92=A+2
A=92-2 =90
X has atomic number =90
and mass number =234
number of neutrons =234-90 =144