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Determine the average life of U^(238) ha...

Determine the average life of `U^(238)` having `t^(1//2)` = 140 days.

Text Solution

Verified by Experts

`t^(1//2)=(0.693)/(lambda)`
`tau=(t^(1//2))/(0.693)`
=202.02 days
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NCERT GUJARATI-NUCLEAR CHEMISTRY-SELF EVALUATION
  1. Determine the average life of U^(238) having t^(1//2) = 140 days.

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  2. The phenomenon of radioactivity was discovered by

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  3. The most penetrating radiations are

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  4. In the nuclear reaction, 92^(X^(232))rarr 89^(Y^(220)), the number of ...

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  5. Which one of the following particles is used to bombard 13^(Al^(27)) t...

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  6. The reaction 5^(B^(8))rarr4^(Be^(8)) takes place due to

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  7. Radioactivity is due to

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  8. In the nuclear reaction, 92^(X^(232))rarr 89^(Y^(220)), the number of ...

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  9. 92^(U^(235)) nucleus absorbs a neutron and disintegrates into 54^(Xe^(...

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  10. Loss of a beta-particle is equivalent to

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  11. Which of the following is used as neutron absorber in the nuclear reac...

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  12. What is half life period.

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  13. Write two difference between chemical reaction and nuclear reaction.

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  14. What is Q value of a nuclear reaction?

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  15. State two uses of radio carbon dating.

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  16. How many alpha and beta particles will be emitted by an element 84^(A^...

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  17. Calculate the decay constant for Ag^(108) if its half life is 2.31 min...

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  18. Complete the following nuclear reactions (i) 18^(Ar^(40)) + ? ra...

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  19. Calculate the number of alpha and beta particles emitted in the conver...

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  20. The atomic mass of Th is 232 and its atomic number is 90. In terms of ...

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  21. Calculate the average life of 79A^(Au^(198)) leaving t^(1//2) = 150 da...

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