Home
Class 12
PHYSICS
Answer the following questions: (d) Tw...

Answer the following questions:
(d) Two students are separated by a 7 m partition wall in a room 10 m high. If both light and sound waves can bend aroundobstacles, how is it that the students are unable to see each other even though they can converse easily.

Text Solution

Verified by Experts

For diffraction or bending of waves by obstacles/apertures by a large angle, the size of the latter should be comparable to wavelength. If the size of the obstacle/aperture is much too large compared to wavelength, diffraction is by a small angle. Here the size is of the order of a few metres. The wavelength of light is about `5xx 10^(-7m)`, while sound waves of, say, 1 kHz frequency have wavelength of about 0.3 m. Thus, sound waves can bend around the partition while light waves cannot.
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    NCERT GUJARATI|Exercise EXERCISES|26 Videos
  • SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|8 Videos

Similar Questions

Explore conceptually related problems

The transverse displacement of a string (clamped at its both ends) is given by y(x, t) = 0.06 sin ((2 x)/(3) x) cos (120 pi t) where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3.0 xx 10^(-2) kg . Answer the following : (a) Does the function represent a travelling wave or a stationary wave? (b) Interpret the wave as a superposition of two waves travelling in opposite directions. What is the wavelength, frequency , and speed of each wave ? (c ) Determine the tension in the string.

A student performs an experiment to determine how the range of a ball depends on the velocity with which it is projected. The "range" is the distance between the points where the ball lends and from where it was projected, assuming it lands at the same height from which it was projected. It each trial, the student uses the same baseball, and launches it at the same angle. Table shows the experimental results. |{:("Trail","Launch speed" (m//s),"Range"(m)),(1,10,8),(2,20,31.8),(3,30,70.7),(4,40,122.5):}| Based on this data, the student then hypothesizes that the range, R, depends on the initial speed v_(0) according to the following equation : R=Cv_(0)^(n) , where C is a constant and n is another constant. The student performs another trial in which the ball is launched at speed 5.0 m//s . Its range is approximately:

A student performs an experiment to determine how the range of a ball depends on the velocity with which it is projected. The "range" is the distance between the points where the ball lends and from where it was projected, assuming it lands at the same height from which it was projected. It each trial, the student uses the same baseball, and launches it at the same angle. Table shows the experimental results. |{:("Trail","Launch speed" (m//s),"Range"(m)),(1,10,8),(2,20,31.8),(3,30,70.7),(4,40,122.5):}| Based on this data, the student then hypothesizes that the range, R, depends on the initial speed v_(0) according to the following equation : R=Cv_(0)^(n) , where C is a constant and n is another constant. The student speculates that the constant C depends on :- (i) The angle at which the ball was launched (ii) The ball's mass (iii) The ball's diameter If we neglect air resistance, then C actually depends on :-

A student performs an experiment to determine how the range of a ball depends on the velocity with which it is projected. The "range" is the distance between the points where the ball lends and from where it was projected, assuming it lands at the same height from which it was projected. It each trial, the student uses the same baseball, and launches it at the same angle. Table shows the experimental results. |{:("Trail","Launch speed" (m//s),"Range"(m)),(1,10,8),(2,20,31.8),(3,30,70.7),(4,40,122.5):}| Based on this data, the student then hypothesizes that the range, R, depends on the initial speed v_(0) according to the following equation : R=Cv_(0)^(n) , where C is a constant and n is another constant. Based on this data, the best guess for the value of n is :-

A double pan window used for insulating a room thermally from outside consists of two glass sheets each of area 1 m^(2) and thickness 0.01m separated by 0.05 m thick stagnant air space. In the steady state, the room-glass interface and the glass-outdoor interface are at constant temperatures of 27^(@)C and 0^(@)C respectively. The thermal conductivity of glass is 0.8 Wm^(-1)K^(-1) and of air 0.08 Wm^(-1)K^(-1) . Answer the following questions. (a) Calculate the temperature of the inner glass-air interface. (b) Calculate the temperature of the outer glass-air interface. (c) Calculate the rate of flow of heat through the window pane.

When a particle is restricted to move aong x axis between x =0 and x = a , where a is of nanometer dimension. Its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends x = 0 and x = a . The wavelength of this standing wave is realated to the linear momentum p of the particle according to the de Breogile relation. The energy of the particl e of mass m is reelated to its linear momentum as E = (p^(2))/(2m) . Thus, the energy of the particle can be denoted by a quantum number 'n' taking values 1,2,3,"......." ( n=1 , called the ground state) corresponding to the number of loop in the standing wave. Use the model decribed above to answer the following three questions for a particle moving in the line x = 0 to x =a . Take h = 6.6 xx 10^(-34) J s and e = 1.6 xx 10^(-19) C . If the mass of the particle is m = 1.0 xx 10^(-30) kg and a = 6.6 nm , the energy of the particle in its ground state is closet to

When a particle is restricted to move aong x axis between x =0 and x = a , where a is of nanometer dimension. Its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends x = 0 and x = a . The wavelength of this standing wave is realated to the linear momentum p of the particle according to the de Breogile relation. The energy of the particl e of mass m is reelated to its linear momentum as E = (p^(2))/(2m) . Thus, the energy of the particle can be denoted by a quantum number 'n' taking values 1,2,3,"......." ( n=1 , called the ground state) corresponding to the number of loop in the standing wave. Use the model decribed above to answer the following three questions for a particle moving in the line x = 0 to x =a . Take h = 6.6 xx 10^(-34) J s and e = 1.6 xx 10^(-19) C . The speed of the particle, that can take disrete values, is proportional to

When a particle is restricted to move aong x axis between x =0 and x = a , where a is of nanometer dimension. Its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends x = 0 and x = a . The wavelength of this standing wave is realated to the linear momentum p of the particle according to the de Breogile relation. The energy of the particl e of mass m is reelated to its linear momentum as E = (p^(2))/(2m) . Thus, the energy of the particle can be denoted by a quantum number 'n' taking values 1,2,3,"......." ( n=1 , called the ground state) corresponding to the number of loop in the standing wave. Use the model decribed above to answer the following three questions for a particle moving in the line x = 0 to x =a . Take h = 6.6 xx 10^(-34) J s and e = 1.6 xx 10^(-19) C . The allowed energy for the particle for a particular value of n is proportional to

NCERT GUJARATI-WAVE OPTICS-EXERCISES
  1. In a double-slit experiment the angular width of a fringe is found to ...

    Text Solution

    |

  2. What is the Brewster angle for air to glass transition? (Refractive in...

    Text Solution

    |

  3. Light of wavelength 5000 Å falls on a plane reflecting surface. What a...

    Text Solution

    |

  4. Estimate the distance for which ray optics is good approximation for a...

    Text Solution

    |

  5. The 6563Å Halpha line emitted by hydrogen in a star is found to be red...

    Text Solution

    |

  6. Explain how Corpuscular theory predicts the speed of light in a medium...

    Text Solution

    |

  7. You have learnt in the text how Huygens’ principle leads to the laws o...

    Text Solution

    |

  8. Let us list some of the factors, which could possibly influence the sp...

    Text Solution

    |

  9. For sound waves, the Doppler formula for frequency shift differs sligh...

    Text Solution

    |

  10. In double-slit experiment using light of wavelength 600 nm, the angula...

    Text Solution

    |

  11. Answer the following questions: (a) In a single slit diffraction exp...

    Text Solution

    |

  12. Answer the following questions: (b) In what way is diffraction from ...

    Text Solution

    |

  13. Answer the following questions: (c) When a tiny circular obstacle is...

    Text Solution

    |

  14. Answer the following questions: (d) Two students are separated by a ...

    Text Solution

    |

  15. Answer the following questions: (e) Ray optics is based on the assum...

    Text Solution

    |

  16. Two towers on top of two hills are 40 km apart. The line joining them ...

    Text Solution

    |

  17. A parallel beam of light of wavelength 500 nm falls on a narrow slit a...

    Text Solution

    |

  18. Answer the following questions: (a) When a low flying aircraft passe...

    Text Solution

    |

  19. Answer the following questions: (b) As you have learnt in the text, ...

    Text Solution

    |

  20. In deriving the single slit diffraction pattern, it was stated that th...

    Text Solution

    |