The charges of an electric dipole are respectively `32xx10^(-7)` coulomb and `-32xx10^(-7)` coulomb are separated by a distance of 10 cm . Find the field at a point situated at a distance of 8 cm from each charge.

Explanation

Suppose `E_(1)` is the field due to `+32xx10^(-7)` coulomb charge and `E_(2)` is the field due to the `-32xx10^(-7)` coulomb charge at C, then

`E_(1)=(1)/(4piepsilon_(0))(q_(1))/(r^(2))`
`=(9xx10^(9)xx32xx10^(-7))/((0.8)^(2))`
`=4.5xx10^(6)N//C` . Along CP
and `E_(2)=(9xx10^(9)xx32xx10^(-7))/((.08)^(2))`
`=4.5xx10^(6)N//C`. Along CQ
But from `Delta.s` PCR and CAB
`(CR)/(AB)=(CP)/(CA)`
or `(E)/(0.1)=(4.5xx10^(6))/(.08)`
or , `E=(0.10xx4.5xx10^(6))/(.08)`
`=5.625xx10^(6)`
`E=5.625xx10^(6)("newton")/("coulomb")`