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In the first excited state of hydrogen a...

In the first excited state of hydrogen atom, its radius is found to be `21.2xx10^(-11)` m. Calculate its Bohr radius in the ground state. Also calculate the total energy of the atom in the second excited state.

Text Solution

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First excited state means,
n=2
`r_(0)=n^(2)r_(1)`
`r_(1)=(21.2xx10^(-11))/(4)`
`=5.3xx10^(11)m`
`E=-(13.6)/(n^(2))=-3.4eV`.
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