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The solubility of AgCl in 0.1M NaCI is (...

The solubility of AgCl in 0.1M NaCI is `(K_(sp) " of AgCl" = 1.2 xx 10^(-10)) `

A

0.1 M

B

1.2 `xx 10^(-5)`

C

`1.095 xx 10^(-5)`

D

`1.2 xx 10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
D
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