The number of alpha and beta emitted in ...

The number of `alpha and beta` emitted in the nuclear reaction `""_(92)^(238)U to ""_(82)^(214)Pb` is

`8 beta`

`6 alpha`

`2 beta`

`5 alpha`

Text Solution

Verified by Experts

The correct Answer is:

B, C

Let x `alpha- and y beta`- particle be emitted in the reaction.
`""_(92)^(238)U to x ""_(2)^(4)alpha + y ""_(-1)^(0)beta + ""_(82)^(214)Pb`
Equating the mass numbers on both sides,
`238 = 4x + y xx 0 + 214 implies 4x = 24 :. x = 6`
Equating atomic numbers on both sides,
`92 = 2x + (-y) + 82`
`92 = 2 xx 6 + (-y) + 82 implies - y = - 2 :. y = 2`
Hence in the nuclear reaction, `""_(92)^(238)U to ""_(82)^(214)Pb, 6 alpha`- and `2 beta` - particles are emitted.

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The total number of alphaandbeta particles emitted in the nuclear reaction ""_(92)^(238)Uto""_(82)^(214)Pb is

The number of alpha and beta -particle emitted in the transformation ""_(92)^(238)U to ""_(92)^(234)U

1,1

1,0

1,2

2,1

The number of alpha beta - particles emitted in the nucleus reaction ._(92)U^(238) rarr ._(90)Th^(234) rarr ._(91)Pa^(234) are respectively

1 and 1

1 and 2

2 and 1

2 and 2