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In the circuit shown, R1=2 Omega,R2=R3=1...

In the circuit shown, `R_1=2 Omega,R_2=R_3=10Omega and E=6V`. Work out the equivalent resistance of the circuit and the current in each resistor.

Text Solution

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`R_3 and R_4` are in parallel combination.

`1/R_34=1/R_3+1/R_4=1/5+1/10=(2+1)/10=3/10rArrR_34=10/3=3.3 Omega`
`R_34andR_2` are in parallel combination `1/R_234=1/R_34+1/R_2=10/3.3+1/5`
`(50+33)/165=83/165rArrR_234=165/83=1.98Omega`
`R_234 and R_1` are in series combination.
`R_1234=R_234+R_1`
`=1.98+4=2.02Omega`.
`I=V/R=6/2.02=2.97A`.
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