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An electron and a photon each have a wavelength of 2.00nm. Find (i) their momenta (ii) the energy of the photon and (iii) the kinetic energy of electron. `h=6.63xx10^(-34)Js`

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(a) For electron or photon, momentum,
`p=h/lambda=(6.63xx10^(-34))/(2xx10^(-9))=3.31xx10^(-25)m`.
(b) `E=(hC)/lambda=((6.63xx10^(-34))xx(3xx10^8))/((2xx10^9-9)xx(1.6xx10^(-19)))=621.5m`
(c ) `E_k=1/2p^2/m=1/2=((6.63xx10^(-25))^2)/((9xx10^(-31))(1.6xx10^(-19)))=1.52eV`.
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