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A series LCR circuit with L = 4.0 H, C =...

A series LCR circuit with `L = 4.0 H, C = 100 mu F` and `R = 60 Omega` is connected to a variable frequency 240 V source. Calculate
(i) angular frequency of the source which drives the circuit in resonance,
(ii) current at the resonating frequency,
(iii) rms potential drop across the inductance at resonance.

Text Solution

Verified by Experts

(i) Angular frequency
(i) `omega=(1)/(sqrt(LC))=(1)/(sqrt(4xx100xx10^(-6)))=(1)/(2xx10^(-2))=50 rad//s`
`(ii) I=(V_(rms))/(Z)=(V_(rms))/(R )(240)/(60)=4A`
(iii) `V_(rms) " across" L=4xx x_(L)=4xx(1)/(2xx10^(-2))xx4.0=800 " volt"`.
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