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A light bulb is rated 200 W for 220 V s...

A light bulb is rated 200 W for 220 V supply at 50 Hz. Calculate resistance of the bulb and rms current through the bulb.

Text Solution

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(i) Resistance of the bulb
`R=(E^(2))/(P)=((220)^(2))/(200)=242 Omega.`
(ii) Peak voltage
`V_(0)=Vsqrt(2)=200 sqrt(2)=311 V.`
rms current through the bulb,
`I=(P)/(E )=(311)/(220)=0.450 A.`
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