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An alternating voltage given by E = 28...

An alternating voltage given by
`E = 280 sin 50 pi t` is connected across a pure resistor of 40 ohm. Find frequency of source and rms current through the bulb.

Text Solution

Verified by Experts

(i) `V_(0)=280 V,`
`omega = 50 pi rArr 2pi v = 50 pi rArr v=25 Hz`
(ii) `I_(rms)=(V_(rms))/(R)=(V_(0)//sqrt(2))/(R)=(280)/(sqrt(2)xx40)=3.5xx1.414=4.95 A.`
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