An alternating voltage given by `V=70 sin 100 pi t` is connected across a pure resistor of `25 Omega.` Find
(i) the frequency of the source.
(ii) the rms current through the resistor.

Explanation

`V_(0)=70, omega =100 pi`
(i) `2piV=100 pi therefore V=50 Hz`
(ii) `I_(rms)=(V_(rms))/(R ) =(V_(0)//sqrt(2))/(R )=(70)/(sqrt(2xx25))`
`=(14)/(5xx1.414)=1.98` ampere.