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A parallel plate capacitar, of capacitan...

A parallel plate capacitar, of capacitance, `20 mu F`, is connected to a 100 V supply. After some time, the battery is disconnected , and the space, between the plates of the capacitor is filled with a dielectric, of dielectric constant 5. Calculate the energy stored in the capacitar (i) before (ii)after dielectric has been put in between its plates.

Text Solution

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`U_0=(1)/(2) CV^2=(1)/(2)xx 20xx 10^-6 xx 100x 100=0.1J`
After battery is disconnected and dielectric is filled
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