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A proton, a deuteron and an alpha partic...

A proton, a deuteron and an alpha particle, are accelerated through the same potential difference and then subjected to a unifrom magnetic field `vecB`, perpendicular to the direction of their motions. Compare (i) their kinetic energies, and (ii) if the radius of the ciruclar path described by proton is 5 cm, determine the radii of the paths described by deuteron and alpha partcile.

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the kinetic energy of the particles and the radius of their paths in a magnetic field. ### Step 1: Understanding the Kinetic Energy When charged particles are accelerated through a potential difference \( V \), their kinetic energy \( KE \) is given by the formula: \[ KE = qV \] where \( q \) is the charge of the particle. ...
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Knowledge Check

  • A proton, a deuteron and an alpha particle are accelerated through same potential difference and then they enter a normal uniform magnetic field, the ratio of their kinetic energies will be

    A
    `2:1:3`
    B
    `1:1:2`
    C
    `1:1:1`
    D
    `1:2:4`

  • A proton, a deutron and an alpha - particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to it. What is the ratio of their kinetic energy?

    A
    `1:1:2`
    B
    `2:2:1`
    C
    `1:2:1`
    D
    `2:1:1`

  • A proton and alpha particle, after accelerating through same potential difference enters into a uniform magnetic field perpendicular to their velocities, find the radius ratio of proton and alpha particle:-

    A
    `1:2`
    B
    `1:1`
    C
    `2:1`
    D
    `1:sqrt2`

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