The figure shows arectangular conducting frame MNOP of resistance R placed partly in a perpendicular magnetic field `vecB` and moved with velocity `vecV` as shown in the figure.
Obtain the expressions for the
(a) force acting on the arm 'ON' and its direction, and
(b) power required to move the frame to get a steady emf induced between the arms MN and PO.

Explanation

(a) There will be no force on the arm ON it's outside the magnetic field when the wire enter the magnetic field it will experience the force F=Bil in the direction opposite to the direction of velocity.
(b) P=Fv
=Bilv
`=B((Bvl)/(R ))vl`
`P=(B^(2)v^(2)l^(2))/(R)`
`as" "F=BIl`
`I=(Bvl)/(R)`