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int (cos2x)/(cosx) dx=...

`int (cos2x)/(cosx) dx=`

A

`2sinx+log|secx+tanx|+c`

B

`2sinx-log|secx-tanx|+c`

C

`2sinx-log|secx+tanx|+c`

D

`2sinx+log|secx-tanx|+c`

Text Solution

Verified by Experts

The correct Answer is:
C, D
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