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Let f: N -> R be such that f(1) = 1 and ...

Let `f: N -> R` be such that `f(1) = 1` and `f(1) + 2f(2) + 3f(3) + nf(n)`, for all `n in N, n >= 2`, where N is the set of natural numbers and R is the set of real numbers. Then the value of `f(500)` is

A

1000

B

500

C

1/500

D

1/1000

Text Solution

Verified by Experts

The correct Answer is:
D
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