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Let f(x)={x^2|(cos)pi/x|, x!=0 and 0,x=0...

Let `f(x)={x^2|(cos)pi/x|, x!=0 and 0,x=0,x in RR,` then `f` is

A

differentiable at both x = 0 and x = 2

B

differentiable at x = 0 but not differentiable at x = 2

C

not differentiable at x = 0, but differentiable at x = 2

D

differentiable at neither x = 0 nor x = 2.

Text Solution

Verified by Experts

The correct Answer is:
B
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