The percentage error in the mass and speed are 2% and 3% respectively. What is the maximum error in kinetic energy calculated using these quantities?

Explanation

`(Delta m)/(m) xx 100 = 2% , (Delta v)/(v) xx 100 = 3%`.
Kinetic energy, `E = 1/2 mv^2 `
maximum error in kinetic energy
`(Delta E)/(E ) xx 100 = (Delta m)/(m) xx 100 + 2 (Delta v)/(v) xx 100`
Maximum error in kinetic energy
`= 2% + 2 xx 3% = 2% + 6% = 8%`.