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The dimensional formula of the product o...

The dimensional formula of the product of two physical quantities P and Q is `ML^2 T^(-2)`. The dimensional formula of `P//Q` is `ML^0 T^(-2)`. Then what are the units of physical quantities P and Q.

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Given `P xx Q` has dimensions `ML^2 T^(-2)`
`P//Q` has dimensions `ML^(0)T^(-2)`
Hence, `(PQ)(P/Q) = (ML^2 T^(-2))(ML^0T^(-2))`
`P^2 = M^2 L^2 T^(-4)`
`:. P = ML^1 T^(-2)` = Force `" " …….(1)`
given `P/Q = M^(1)L^(0)T^(-2) , (ML^1 T^(-2))/(Q) = ML^0 T^(-2)`
`Q = (ML^1 T^(-2))/(M L^0 T^(-2)) = L = ` Displacement `" "........(2)`
`:.` P and Q are respectively the force and the displacement, hence their units are newton and metre.
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