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A circular coil A has a radius R and cur...

A circular coil A has a radius R and current flowing through it is I. Another circular coil B has a radius 2R and if 2I is the current flowing throgh it, then the magneitc field at the centre of the circular coil are in the ratio (i.e, `B_A` to `B_B`) of

A

`4:1`

B

`2:1`

C

`3:1`

D

`1:1`

Text Solution

Verified by Experts

The correct Answer is:
A

`B_A = (mu_0 I)/(2R) and B_B = (mu_0 (2I))/(2(2R)) = (mu_0 I)/(2R) implies B_A : B_B = 1 : 1`
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