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A charged particle is moving in a circul...

A charged particle is moving in a circular path under the action of the Lorentz force. How much work is done by the force in one revolution?

Text Solution

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Zero, because force is acting perpendicular to the direction of motion of the charged particle.
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Knowledge Check

  • Statement 1: A charged particle is moving in a circular path under the action of a uniform magnetic field as shown in Fig. During motion kinetic energy of charged particle is costant. Statement 2: During the motion, magnetic force acting on the particle is perpendicular to instantaneous velocity.

    A
    If both statement 1 and statement 2 are ture, statement 2 is the correct explanation of statement 1.
    B
    If both statement 1 and statement 2 are ture, statement 2 is not the correct explanation of statement 1.
    C
    If statement 1 is true, statement 2 is false.
    D
    If statement 1 is false, statement 2 is true.

  • A particle is moving in a circular path of radius r under the action of a force F. If at an instant velocity of particle is v, and speed of particle is increasing, then

    A
    `vecF.vecv=0`
    B
    `vecF.vecc gt 0`
    C
    `vecF.vecv lt0`
    D
    `vecF.vecvge0`

  • A particle 'P' is moving on a circular under the action of only one force action always toward the fixed point 'O' on the circumference. Find the ratio of (d^(2)theta)/(dt^(2)) & (("d"theta)/(dt))^(2)

    A
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    B
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    C
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    D
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