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The ground state energy of hydrogen atom...

The ground state energy of hydrogen atom is - 13.6 eV. When its electron is in the first excited state, its excitation energy is.

A

6.8 eV

B

10.2eV

C

0

D

3.4 eV

Text Solution

Verified by Experts

The correct Answer is:
B

`E_(1) = - 13.66 eV`
In first excited state `E_(2) = (13.6)/((2)^(2)) = -3.4 eV`
`therefore ` Excitation energy ` = E_(2) = E_(1) = - 3.4 - (-13.6) eV = + 10.2 eV`
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