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The energy of electron in first excited ...

The energy of electron in first excited state of H-atom is - 3.4 eV. Its kinetic energy is.

A

-3.4 eV

B

`+3.4 eV`

C

`-6.8 eV`

D

`+6.8 eV`

Text Solution

Verified by Experts

The correct Answer is:
B
`K= - E = - (-3.4e V) = + 3.4 eV`
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