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In the nth stable orbit of a hydrogen at...

In the nth stable orbit of a hydrogen atom, the energy of an electron ` E = -(13.6)/(n^(2))` eV. The energy required to take the electron from first orbit to second orbit will be

A

10.2 eV

B

12.1 eV

C

13.6 eV

D

3.4 eV

Text Solution

Verified by Experts

The correct Answer is:
A
Energy required ` E = E_(2) - E_(1) = (-13.6)/((2)^(2)) - [-(13.6)/((1)^(2))] = - 3.4 + 13.6 = + 10.2 eV`
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