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Energy of an electron in an excited stat...

Energy of an electron in an excited state of hydrogen atom is - 3.4 eV. Its angular momentum will be

A

`1.11 xx 10^(-34)` Js

B

`1.51 xx 10^(-34) Js`

C

`2.11 xx 10^(-34) Js`

D

`3.72 xx 10^(-34) Js`

Text Solution

Verified by Experts

The correct Answer is:
C
Energy E = 3.4 eV correponds to n = 2 state of hydrogen atom hence its angular momentum `= (nh)/(2pi) =(2xx6.63 xx 10^(-34))/(3xx3.14) = 2.11 xx 10^(-34)Js`.
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