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An electron is accelerated through a pot...

An electron is accelerated through a potential difference of 100 V, then de-Broglie wavelength associated with it is approximately ___________`Å`.

Text Solution

Verified by Experts

The correct Answer is:
`1.227Å`
Hint : de- Broglie wavelength of electron `lambda=(12.27)/(sqrtV)Å=(12.27)/(sqrt(100))Å=1.227A`
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