The nearest neighbouring silver atoms in the silver crystals are `2.87 xx 10^(-10)` m apart. What is the density of silver ? Silver crystallises in fcc form. [Atomic mass of Ag = 108]

Explanation

Nearest neighbours if fcc crystal `=(1)/(2)xx" Face diagonal"=(1)/(2)(sqrt2a)`
`"or "2.87xx10^(-10)m=(a)/(sqrt2)`
`"or "a=2.87xx1.414xx10^(-10)=4.05xx10^(-10)m=4.05xx10^(-8)cm`
`"or Volume "=a^(3)=(4.05)^(3)xx10^(-24)`
Use the following equation to calculate d
`d=(zxxM)/(a^(3)xxN_(A))=(4xx108)/((4.05)^(3)xx10^(-24)xx6.023xx10^(23))=(108)/(1.008xx10)=(108)/(10.08)="10.7 g cm"^(-3)`