Home
Class 12
CHEMISTRY
An element with density 11.2 g cm^(-3) f...

An element with density `11.2 g cm^(-3)` forms a fcc lattice with edge length of `4 xx 10^(-8)` cm. Calculate the atomic mass of the element. Give `N_(A) = 6.022 xx 10^(23)` atoms `mol^(-1)`.

Text Solution

Verified by Experts

The correct Answer is:
107.9u
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    U-LIKE SERIES|Exercise LONG ANSWER QUESTION - I|20 Videos
  • SAMPLE QUESTIONS PAPER

    U-LIKE SERIES|Exercise SECTION D|6 Videos
  • SOLUTION

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION D)|2 Videos

Similar Questions

Explore conceptually related problems

An element with density 11.2"g cm"^(-3) forms a fcc lattice with edge length of 4xx10^(-8) cm. Calculate the atomic mass of the element.

An element with density 11.2 g cm^(-3) forms a f. c. c. lattice with edge length of 4xx10^(-8) cm. Calculate the atomic mass of the element. (Given : N_(A)= 6.022xx10^(23) mol^(-1)

(i) (a) Following is the schematic alignment of magnetic moments : What type of magnetism is shown by this substance ? (b) What type of stoichiometric defect is shown by (i) KCI (ii) AgCl ? (ii) An element with density 11.2 g cm^(-3) forms a fcc lattice with length of 4xxd10^(-8) cm. Calculate the atomic mass of the element. (N_(A)=6.02xx10^(23) mol^(-1)) .

An element with density 2.8 cm^(3) forms a f.c.c unit cell with edge length 4xx10^(-8) cm. calculate the molar mass of the element. Given: (N_(A)=6.022xx10^(23)) mol^(-1)

An element with density 10 g cm^(-3) forms a cubic unit cell with edge length 3xx10^(-8)cm . What is the nature of the cubic unit cell if the atomic mass of the element is 81 g mol^(-1) .