The sum of first three terms of a G.P. is `(13)/(12)`and their product is ` 1`. Find the common ratio and the terms.

Explanation

To solve the problem, we need to find the common ratio and the terms of a geometric progression (G.P.) given that the sum of the first three terms is \( \frac{13}{12} \) and their product is \( 1 \).

### Step 1: Define the terms of the G.P.
Let the first term be \( a \) and the common ratio be \( r \). The first three terms of the G.P. can be expressed as:
- First term: \( \frac{a}{r} \)
- Second term: \( a \)
- Third term: \( ar \)

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