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Find the coordinate of the foci, vertice...

Find the coordinate of the foci, vertice eccentricity and the length of the latus rectum of the hyperbola
`49y ^(2) - 16x ^(2) = 784`

Text Solution

Verified by Experts

Given equation is,
`49y^2-16x^2 = 784`
We will convert this equation into standard form.
`=>49/784y^2-16/784x^2 = 1`
`=> y^2/16-x^2/49 =1 `
So, this is our standard equation of hyperbola with,
`a = 4, b = 7`
`c = sqrt(a^2+b^2) = sqrt(16+49) = sqrt65`
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